Integral inequality

Integral inequality

Let $f$ be a continuously differentiable real-valued function on $[0,b]$,
where $b>0$, with $f(0)=0$. Prove that
$$\int\limits_0^b\frac{f(x)^2}{x^2}dx\leq4\int\limits_0^b f'(x)^2dx.$$
Thank you!